At STP, what volume does 0.75 moles of an ideal gas occupy?

At STP, what volume does 0.75 moles of an ideal gas occupy?

• A. 22.4 L
• B. 16.8 L
• C. 33.6 L
• D. 11.2 L

Answer: (B)

At STP, the volume of an ideal gas is 22.4 L per mole. Multiply by the amount in moles: 0.75 × 22.4 L = 16.8 L. So the gas occupies 16.8 liters. You can also confirm with V = nRT/P using P = 1 atm and T = 273.15 K, which gives V ≈ 0.75 × 0.0821 × 273.15 ≈ 16.8 L.

At STP, the volume of an ideal gas is 22.4 L per mole. Multiply by the amount in moles: 0.75 × 22.4 L = 16.8 L. So the gas occupies 16.8 liters. You can also confirm with V = nRT/P using P = 1 atm and T = 273.15 K, which gives V ≈ 0.75 × 0.0821 × 273.15 ≈ 16.8 L.